The ratio of radii of first orbital of h,he+ and li2+ is

1.	The ratio of radii of first orbital of h,he+ and li2+ is
Answer» $He^+$ $Li^{<klux>2</klux>+}$ Thus the ratio of radii of first orbital of H , and is 3: 2: 1 Explanation: Radius of an atom is given by the Bohr's equation: $r=\frac{0.529\times n^2}{Z}A^0$ where, r = radius of atom n = number of orbit, for first n = 1, for second n = 2 and so on. Z = ATOMIC number a) For first orbital of H $r=\frac{0.529\times 1^2}{1}A^0$ $r=0.529A^0$ $He^+$ B) For first orbital of $r=\frac{0.529\times 1^2}{2}A^0$ $r=0.264A^0$ $Li^{2+}$ b) For first orbital of $r=\frac{0.529\times 1^2}{3}A^0$ $r=0.176A^0$ $He^+$ $Li^{2+}$ Thus the ratio of radii of first orbital of H , and is 3: 2: 1 Learn more about Bohr radius brainly.in/question/3266241 brainly.in/question/276068

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