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The ratio of product of radius and time period of electron orbiting in 2nd and 3rd orbit hydrogen atom |
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Answer» Ratio of nth orbit = \(k\frac{n^2}{z}\) where k= constant and n = no of orbit Here z =1 (for hydrogen atom) Now, n for 3rd orbit = n2 = 9 n for 2nd orbit = n2 = 4 K is constant and Z =1 \(\frac{r_2}{r_3}\) \(=\frac{4}{9}\) |
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