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The ratio of fe3+ and fe2+in fe0..9s1.0 is​

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Fe3+= x and Fe2+=.93-x. USING charge balance: 3*x+2*(0.93-x) = 2*1. ( 1 for oxygen). x = .14. % of Fe3+= (.14/.93)* 100. =15%. This conversation is already

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