1.

The ratio of energies of electron in the first excited state to its second excited state in H-atom is ......

Answer»

`1:4`
`4:9`
`9:4`
`4:1`

SOLUTION :The ENERGY of ELECTRON `E=(mZ^(2)e^(4))/(8epsi_(0)^(2)h^(2)n^(2))`
`:.Eprop(1)/(2)""` ( `:.` for hydrogen Z=1)
For first excited STATE `n_(1)=2` and `n_(2)=3`,
`:.(E_(1))/(E_(2))=(n_(2)^(2))/(n_(1)^(2))=(9)/(4)"":.E_(1):E_(2)=9:4`


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