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The ratio of atomic number of two elements A and B is `1:2` The numebr of electrons present in the valence sheel `(3^rd)` of A is equal to the difference in the number of electrons present in the other two shells. Steps involved for the calculation of ratio of number of electrons present in a penultimate sheel to anti-penultimate sheel of B are given below : Arrange them in the correct sequence : (1) calculation of atomic number of B (2) calcualtion of valence electrons present in A. (3) calacualtion of atomic number of A. (4) calacualtion of number of electrons present in the penultimate and anti-penultimate shells of B. (5) writing electronic configuration of B.A. 23415B. 23154C. 45231D. 42135 |
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Answer» (i) calculation of valence electorns present in A (ii) calculation of atomic number of A (iii) calcualtion of atomic number of B (iv) writing electronic configuration of B (v) calcualtion of number of electrons present in the penultimate and anti-penultimate shells of B. |
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