The ratio of ages of Kunal and Deepesh is 3:5. After 10 years this rat

1.	The ratio of ages of Kunal and Deepesh is 3:5. After 10 years this ratio becomes 5:7.What is the present age of Deepesh ? (A) 20 years(B) 25 years(C) 50 years(D) 15 years
Answer» SOLUTION : Let KUNAL's AGE be 3x and Deepesh's age be 5x After 10 years : • Kunal's age = 3x + 10 and • Deepesh's age = 5x + 10 According to the QUESTION : $\longrightarrow \sf \: \dfrac{3x + 10}{5x + 10} = \dfrac{5}{7}$ $\longrightarrow \sf \: 7(3x + 10) = 5(5x + 10)$ $\longrightarrow \sf \: 21x + 70 = 25x + 50$ $\longrightarrow \sf \: 21x - 25x = 50 - 70$ $\longrightarrow \sf \: - 4x = - 20$ $\longrightarrow \sf \: x = \dfrac{20}{4}$ $\longrightarrow \sf \: x = 5 \: years$ $\therefore$ Present age of Deepesh = 5x = 5(5) = 25 years.