The ratio gamma=(C_(P))/(C_(V)) for a gas mixture consisting of 8 g of helium and 16 g of oxygen is

The ratio gamma=(C_(P))/(C_(V)) for a gas mixture consisting of 8 g of

1.	The ratio gamma=(C_(P))/(C_(V)) for a gas mixture consisting of 8 g of helium and 16 g of oxygen is
Answer» `(23)/(15)` `(15)/(23)` `(27)/(11)` `(17)/(27)` Solution :Helium is a MONO atomic gas and oxygen is diatomic gas. `C_(P)= of O_(2)= (7)/(2) R,C_(P) "of helium"= (5)/(2)R,n_(1) "of oxygen"=2` `C_(V) of O_(2)= (5)/(2)R , C_(V) "of helium"= (3)/(2)R, n_(2) "of oxygen"=0.5` `gamma_("mix")= (n_(1)C_(P_(1))+ n_(2)C_(P_(2)))/(n_(1)C_(V_(1))+ n_(2)C_(V_(2)))= (2 xx (5)/(2)R+ (1)/(2) xx (7)/(2) R)/(2 xx(3)/(2)R+ (1)/(2) xx (5)(2)R)= (27)/(17)`