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The ratio between the root mean square speed of `H_(2)` at `50 K` and that of `O_(2)` at `800 K` isA. `4`B. `2`C. `1`D. `1//4` |
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Answer» `v_(rms)=sqrt((3RT)/(M))` For `H_(2)` at `50 K`, `v_(1)=sqrt((3Rxx50)/(2))` For `O_(2)` at `800 K`, `v_(2)=sqrt((3Rxx800)/(32))` `:. (v_(1))/(v_(2))=(sqrt((3Rxx50)/(2)))/(sqrt((3Rxx800)/(32)))=1` |
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