1.

The rate of formation of ammonia by the reaction: N_2 +3H_2 to 2NH_3 expressed as (d[NH_3])/(dt)= 2.5xx 10^(-4)molL^(-1)s^(-1) The rate of consumption expressed in terms of H_2 as (-d[H_2])/(dt) will be

Answer»

double
THREE times
Same
one and a HALF TIME of that EXPRESSED in terms of `NH_3`

SOLUTION :`1/2(dNH_3])/(dt)=-1/3(d[H_2])/(dt) or -(d[H_2])/(dt)=3/2xx(d[NH_3])/(dt)`


Discussion

No Comment Found

Related InterviewSolutions