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The rate of flow in stream with 40% O2 and 60% CO2 is 10 mole/hr, the contained was initially filled with 6 mole of O2, what will be the percentage of O2 in product stream?(a) 12.5(b) 25(c) 50(d) 62.5 |
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Answer» Correct answer is (d) 62.5 To explain I would say: Percentage of O2 = 10/(10 + 6)*100 = 62.5%. |
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