1.

The rate of disintegration of a certain radioactive sample at any instant is `8100` dpm. Fifty minutes later the rate becomes `2700` dpm. The half of the radioactive sample will be (Take `log2=0.3, log3=0.5, log5=0.7`)A. 30 minutesB. 61 minutesC. `47.8` minutesD. `33.3` minutes

Answer» Correct Answer - A
`r_(1)=lamdaN_(1)`
`8100=lamdaN_(@)`
`2700=lamdaN_(t)`
`lamda=(2.303)/50 "log" (N_(@))/(N_(t))=(0.693)/(t_(1//2))`


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