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The rate of diffusion of methane is twice that of `X`. The molecular mass of `X` is divided by `32`. What is value of `x` is ?A. `1`B. `2`C. `3`D. `4` |
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Answer» `r_(CH_(4))=2r_(X)`, we know `r=sqrt((1)/("Molecular mass"))` `:. (r_(CH_(4)))/(r_(X))=sqrt((M_(X))/(M_(CH_(4))implies (2r_(X))/(r_(X))=sqrt((M_(X))/(16))` or `M_(X)=64` Given Molecular mass is divided by `32` therefore, `X=(M_(X))/(32)=(64)/(32)=2` |
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