The rate of diffusion of methane at given temp is twice of a gas x the

1.	The rate of diffusion of methane at given temp is twice of a gas x the molecular wieght of gas x is
Answer» The rate of diffusion of methane at given TEMP is twice of a gas x the molecular weight of gas x is 64. The rate of diffusion of two GASES are compared as follows. $\frac{r1}{r2} = \sqrt{\frac{M1}{M2}}$ As The rate of diffusion of methane at given temp is twice of a gas x the molecular weight of gas x is 64. Hence, $\frac{r1}{2r1} = \sqrt{\frac{16}{M2}}$ $\frac{1}{2} = \sqrt{\frac{16}{M2}}$ Squaring both sides to remove the square root. $(\frac{1}{2})^{2} = (\sqrt{\frac{16}{M2}})^{2}$ Then we will get after squaring both sides,Then we will get after squaring both sides, $\frac{1}{4} = \frac{16}{M2}$ M2 = 64 Detailed SOLUTION and explanation is given in the attachment

The rate of diffusion of methane at given temp is twice of a gas x the molecular wieght of gas x is

Answer»

The rate of diffusion of methane at given TEMP is twice of a gas x the molecular weight of gas x is 64.

The rate of diffusion of two GASES are compared as follows.

$\frac{r1}{r2} = \sqrt{\frac{M1}{M2}}$

As The rate of diffusion of methane at given temp is twice of a gas x the molecular weight of gas x is 64.

Hence,

$\frac{r1}{2r1} = \sqrt{\frac{16}{M2}}$

$\frac{1}{2} = \sqrt{\frac{16}{M2}}$

Squaring both sides to remove the square root.

$(\frac{1}{2})^{2} = (\sqrt{\frac{16}{M2}})^{2}$

Then we will get after squaring both sides,Then we will get after squaring both sides,

$\frac{1}{4} = \frac{16}{M2}$

M2 = 64

Detailed SOLUTION and explanation is given in the attachment