The rate constant of a reaction is 2*10⁻³ min⁻¹ at 300 K temperature.By increase in temperature by 20 K, its value becomes three time; then calculate the energy of activation of the reaction.What will be its rate constant at 310 K temperature? Calculate the given example.

The rate constant of a reaction is 2*10⁻³ min⁻¹ at 300 K tempera

1.	The rate constant of a reaction is 2*10⁻³ min⁻¹ at 300 K temperature.By increase in temperature by 20 K, its value becomes three time; then calculate the energy of activation of the reaction.What will be its rate constant at 310 K temperature? Calculate the given example.
Answer» TION:OH no I don't KNOW this ANSWER SORRY