The rate constant for the first-order reaction, 2N2O5 → 4NO2 + O2 is – InterviewSolution

1.	The rate constant for the first-order reaction, 2N2O5 → 4NO2 + O2 is 3.0 × 10−5 s−1. If the rate is 2.40 × 10−5 molL s−1, then the initial concentration of N2O5 (in molL) is
Answer» The rate constant for the first-order reaction, 2 $N_{2}$ $O_{5}$ $\to$ 4 ${N O}_{2}$ + $O_{2}$ is 3.0 $\times$ $10^{- 5}$ $s^{- 1}$ . If the rate is 2.40 $\times$ $10^{- 5}$ $\frac{m o l}{L}$ $s^{- 1}$ , then the initial concentration of $N_{2}$ $O_{5}$ (in $\frac{m o l}{L}$ ) is

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