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The rate constant for a first order reaction is 4.606 × 10–3 s–1 . The time required to reduce 2.0 g of the reactant to 0.2 g is : (1) 1000 s (2) 100 s(3) 200 s (4) 500 s |
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Answer» (4) 500 s k = 4.606 × 10–3 s–1 kt = 2.303log10 2/0.2 4.606 x 10-3 x t = 2.303 x log10 t = 1000/2 = 500s |
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