1.

The rate constant for a first order reaction is 4.606 × 10–3 s–1 . The time required to reduce 2.0 g of the reactant to 0.2 g is : (1) 1000 s (2) 100 s(3) 200 s (4) 500 s

Answer»

(4) 500 s

k = 4.606 × 10–3 s–1

kt = 2.303log10 2/0.2

4.606 x 10-3 x t = 2.303 x log10

t = 1000/2

= 500s



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