1.

The range of a projectile fired at angle of 15^@ is 50m. If it is fired with the same speed at an angle of 45^@, it's range will be

Answer»

25 m
50 m
100 m
77.6 m

Solution :`u^2/gsin2xx12^@`=50 `u^2/g = 50/sin30 = 50/(1/2)` = 100
H.R = `u^2/gxxsin2xx45^@=u^2/g =100


Discussion

No Comment Found

Related InterviewSolutions