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The range of a projectile fired at angle of 15^@ is 50m. If it is fired with the same speed at an angle of 45^@, it's range will be |
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Answer» Solution :`u^2/gsin2xx12^@`=50 `u^2/g = 50/sin30 = 50/(1/2)` = 100 H.R = `u^2/gxxsin2xx45^@=u^2/g =100 |
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