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the radius of two circles are 8cm and 6cm respectively find the radius of the circle having its area equal to the the sum of the areas of the two circles. with diagram |
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Answer» Step-by-step explanation: area of first CIRCLE = pi*(8^2) = 64pi are of second circle=pi*(6^2) = 36pi the area of resulting circle = 36pi+64pi = 100pi the radius of new circle = sqrt(100pi/pi) = sqrt(100) = 10 sqrt(x) represent SQUARE root of x the radius of new circle = 10 CM |
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