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The radius of the earth and the radius of orbit around the sun are 6371 km and `149 xx 10^(6)` km respectively. The order of magnitude of the diameter of the orbit is greater than that of earth byA. `10^(3)`B. `10^(2)`C. `10^(4)`D. `10^(5)` |
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Answer» Correct Answer - C Given, radius of earth, `R_(e)` = 6371 km and radius of orbit around the sun, `R_(0) =149 xx 10^(6)` km Now, the ratio of the diameters of the earth and orbit around the sun can be expressed as `(D_(0))/(D_(e))=(2R_(0))/(2R_(e))=(2xx14.9xx10^(6))/(2xx6371)=2.33xx10^(4)` From above ratio, it can be concluded that the order of magnitude of the diameter of the orbit is greater than that of earth by multiple of `10^(4)` . |
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