The radius of mercury drop at 20^(@)C is 3mm. If the surface tesion of mercury at this temperature is 4.65xx10^(-1)Nm^(-1). Find the excess presure inside the liquid drop.

The radius of mercury drop at 20^(@)C is 3mm. If the surface tesion of

1.	The radius of mercury drop at 20^(@)C is 3mm. If the surface tesion of mercury at this temperature is 4.65xx10^(-1)Nm^(-1). Find the excess presure inside the liquid drop.
Answer» Solution :Excess PRESSURE `(P)=(2S)/R` Surface tension `(S)=4.6xx10^(-1)Nm^(-1)` radius of the MERCURY drop `r=3=mm=3xx10^(-3)m` `:.P=(2S)/r=(2xx4.65xx10^(-1))/(3xx10^(-3))=310Nm^(-2)`