The radius of mercury drop at 20^(@)C is 3mm. If the surface tension of mercury at this temperature is 4.65xx10^(-1)Nm^(-1). Find the excess pressure inside the liquid drop.

The radius of mercury drop at 20^(@)C is 3mm. If the surface tension o

1.	The radius of mercury drop at 20^(@)C is 3mm. If the surface tension of mercury at this temperature is 4.65xx10^(-1)Nm^(-1). Find the excess pressure inside the liquid drop.
Answer» SOLUTION :Excess PRESSURE `(P)=(2S)/(r )` SURFACE tension `(S)=4.6xx10^(1)Nm^(-1)` radius of the mercury drop = `r=3mm=3xx10^(-3)m` `THEREFORE P=(2S)/(r)=(2xx4.65xx10^(-1))/(3xx10^(-3))=310Nm^(-2)`