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The radius of an orbit of hydrogen atom is 0.85nm. Calculate the velocity of electron in this orbit |
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Answer» Answer: 5.76 m/s. Explanation: Since, the RADIUS of the hydrogen atom is 0.85nm so it will be 0.85*10^-9 meter. Also the atomic number of hydrogen is 1, so Z=1 and the value of the e is given as 1.602*10^-19 J and the value of mass of electron is 9.1*10^-31 kg. So, we KNOW that the velocity of the electron in the orbit will be v^2=Ze^2/rm. So, v=1*1.602*10^-19/√9.1*10^-31)(0.85*10^-9) which on SOLVING we will GET v=1.602*10^-19/2.781*10^-20 which will be EQUAL to 5.76 m/s. |
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