The radius of a hydrogen atom in its ground state is 5.3×10–11 m. After collision with an electron, it is found to have a radius 21.2×10–11 m. Find the value of x where x=6×n and (where n is principal quantum number) (integer only)

The radius of a hydrogen atom in its ground state is 5.3×10–11 m. A

1.	The radius of a hydrogen atom in its ground state is 5.3×10–11 m. After collision with an electron, it is found to have a radius 21.2×10–11 m. Find the value of x where x=6×n and (where n is principal quantum number) (integer only)
Answer» The radius of a hydrogen atom in its ground state is $5.3 \times 10^{- 11} m$ . After collision with an electron, it is found to have a radius $21.2 \times 10^{- 11} m .$ Find the value of $x$ where $x = 6 \times n$ and (where $n$ is principal quantum number) (integer only)

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The radius of a hydrogen atom in its ground state is 5.3×10–11 m. After collision with an electron, it is found to have a radius 21.2×10–11 m. Find the value of x where x=6×n and (where n is principal quantum number) (integer only)

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