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The radius of a He atom is 1×10−9 cm. A 492.6 cm3 container is filled with He at a pressure of 1 atm and a temperature of 300 K . The volume that is occupied by He atom is x×10−6 cm3. Value of x is:(x is rounded off to nearest integer)(Given: R=0.0821 L atm K−1mol−1, π=227 and NA=6×1023) |
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Answer» The radius of a He atom is 1×10−9 cm. A 492.6 cm3 container is filled with He at a pressure of 1 atm and a temperature of 300 K . The volume that is occupied by He atom is x×10−6 cm3. Value of x is: (x is rounded off to nearest integer) (Given: R=0.0821 L atm K−1mol−1, π=227 and NA=6×1023) |
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