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The radius of a circular coil having 50 turns is 2cm. Its plane is normal to the magnetic field. The magnetic field changes from 2T to 4T in 3.14 sec . The induced emf in coil will be |
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Answer» Dear Student, ◆ Answer - EMF = 0.04 V ● EXPLAINATION - # Given - N = 50 turns r = 2 cm = 0.02 m B1 = 2 T B2 = 4 T dt = 3.14 s # Solution - EMF induced in the COIL will be calculated as - EMF = N.dΦ/dt EMF = N.dB.A/dt EMF = 50 × (4-2) × (π×0.02^2) / 3.14 EMF = 50 × 2 × 4×10^-4 EMF = 0.04 V Hence, EMF induced in the coil is 0.04 V. Thanks dear... |
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