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The radius of a circle is 9 cms. Find the length of anarc of this circle which cuts off a chord of lengthequal to length ofradius. |
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Answer» Given: chord CB = 9cm , radii OC = OB = 9 cm < COB = 60° ( as triangle OCB is an equilateral triangle) So, length of arc CB =( sector angle / 360° ) * 2 pi r => (60° / 360° ) 2 pi * 9 = > 18 pi / 6 = 3 pi Length of arc CB = (3 pi) cm |
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