Saved Bookmarks
| 1. |
The radionuclide 11C decays according to11 11 +6 5 1/2 C B+ + : =20.3 min → e T νThe maximum energy of the emitted positron is 0.960 MeV.Given the mass values:m (116C) = 11.011434 u and m (116B ) = 11.009305 u,calculate Q and compare it with the maximum energy of the positron emitted. |
| Answer» The radionuclide 11C decays according to11 11 +6 5 1/2 C B+ + : =20.3 min → e T νThe maximum energy of the emitted positron is 0.960 MeV.Given the mass values:m (116C) = 11.011434 u and m (116B ) = 11.009305 u,calculate Q and compare it with the maximum energy of the positron emitted. | |