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The radioactivity of a given sample of whisky due to tritium (half life `12.3` years) was found to be only `3 %` of that measured in a recently purchased bottle marked `'7` years old'. The sample must have been prepared about.A. Before 70 yearsB. Before 220 yearsC. Before 420 yearsD. Before 300 years |
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Answer» Correct Answer - A We have `N_(1)=N_(0)e^(-lamda xx7)and N_(2)=N_(0)e^(-lamdax)` `(N_(2))/(N_(1))=(3)/(100) = e^(lamda(7-x))or e^(lamda(x+7))=(100)/(3)` `lamda(x-7)= "ln" (100)/(3)~~2.3 log_(10)2.3` `"log"_(10)(100)/(3)=2.3 [2-0.4771]=2.3 xx1.5229` But `lamda =(0.693)/(T_(1//2))=(0.693)/(12.5)` `:. x-7=(12.5)/(0.693)xx2.3 xx1.5229` `~~ (125)/(3)xx1.52 ~~ 63` `:. xx =(63+7)` years = 70 years |
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