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The radii of two pistons in a hydraulic press are 4 cm and 16 cm respectively. A force of \( 25 N \) is applied to the smaller piston. Find the force exerted on the larger piston. |
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Answer» P1 = P2 \(\cfrac{F_1}{\pi{r^2}}=\cfrac{F_2}{\pi{r}2}\) \(\cfrac{25}{(0.04)^2}=\cfrac{F^2}{(0.16)^2}\) F2 = \(\frac{25\times(0.16)^2}{(0.04)^2}\) F2 = \(\frac{0.64}{0.0016}\) F2 = 400N |
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