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The radii of two circles are 8 cm and 6 cm respectively. Find the radius of the circle having its area equal to the sum of the areas of the two circles. |
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Answer» Radius of first circle = 8 cm Area of first circle = πr2 = \(\frac{22}7\times8\times8\) cm2 Radius of second circle = 6 cm Area of second circle = \(\frac{22}7\times6\times6\) cm2 Total area = \(\frac{22}7\times8^2 + \frac{22}7\times6^2\) = \(\frac{22}7({64 +36})\) = \(\frac{22}7\times100\) cm2 πr2 = \(\frac{22}7\times100\) r2 = 100 r = 10 cm |
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