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The radii of curvature of the faces of a double convex lens are 10 cm and 15 cm. If focal length is 12 cm. What is the refractiveindex of glass? |
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Answer» Solution :`f = + 12CM , R_(1) = 10 cm , R_(2) = - 15 cm , n = ?` `As "" (1)/(f) = (n-1)((1)/(R_(1))-(1)/(R_(2)))` `(1)/(12)=(n-1)((1)/(10)+(1)/(15))=(n-1)XX(5)/(30)` `(n-1) = (6)/(12)= 0.5` n = 0.5 + 1 n = 1.5 |
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