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The radiancy of a black body is `M_(e)=3.0W//cm^(2)`. Find the wavelength corresponding to the maximum emmissive capacity of the body. `b=2.9xx10^(-3)m.k`, `sigma=5.67xx10^(-2)K^(-4)`. |
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Answer» `M_(e)=sigmaT^(4)impliesT=4sqrt((M_(e))/(sigma))` Now `lambdaT=bimplieslambda=(b)/(T)=bxx4sqrt(sigma//M_(e))` `implieslambda=2.9xx10^(-3)4sqrt((5.67xx10^(-8))//3.0xx10^(4))=3.4xx10^(-6)m` |
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