Saved Bookmarks
| 1. |
The quantity which does not vary periodically for a particle performing SHM isA. accelerationB. total energyC. displacementD. velocity |
|
Answer» Correct Answer - B For a particle executing simple harmonic motion (SHM), Total energy = kinetic energy + potential energy `=E_(K)+E_(P)=1/2mv^(2)+1/2kx^(2)` `=1/m(A^(2)-x^(2))+1/2momega^(2)A^(2)` `(becausev=sqrt(A^(2)-x^(2))` where, A is the amplitude of the particle`)` `=1/2KA^(2)` It is independent oft, xis remains constant i.e., it does not vary periodically. However, the displacement of a particle executing SHM along x-axis is given by `x=Asin(omegat+phi)` (where, A= amplitude, `omega` = angular velocity t = time, `phi` = initial phase of the particle) i.e., displacement varies periodically with time t. Velocity of particles executing SHM, `v=(dx)/(dt)=omegasqrt(A^(2)-x^(2))` which varies with x. Acceleration of the particle, `a=(dv)/(dt)=-omega^(2)x` Which also varies with x. |
|