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The PV-graph for a monatomic gas is shown in figure. Find the energy absorbedduring this process. Find the energy absorbed by the gasPLEASE GIVE RIGHT ANSWERANSWER IS 8.5BUT HOW????????????​

Answer»

Answer is 8.5 P°V° Explanation:W = Area under PV graph = 5/2 P°V° ◇U = nCv◇T = nCv [ T ( final ) -- T (INITIAL) ] T (initial) = 2 PoVo / nR T (final) = 6 PoVo / nR Cv = 3/2 R hence , ◇U = 6 PoVo SINCE , n = 1 , ◇ Q = heat absorbed by the SYSTEM = ◇U + W = 5/2 PoVo + 6 PoVo Answer = 17/2 PoVo...PLEASE mark this answer if it was helpful



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