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The pth, qth and rh terms of an A.P. are a, b and c respectively.Show that a(q – r) + b(r-p) + c(p - q) = 0 |
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Answer» LET A be the first TERM and D the COMMON difference of A.P. T p =a=A+(p−1)D=(A−D)+pD (1) T q =b=A+(q−1)D=(A−D)+qD ..(2) T R =c=A+(r−1)D=(A−D)+rD ..(3) Here we have got two unknowns A and D which are to be eliminated. We multiply (1),(2) and (3) by q−r,r−p and p−q RESPECTIVELY and add: a(q−r)+b(r−p)+c(p−q) =(A−D)[q−r+r−p+p−q]+D[p(q−r)+q(r−p)+r(p−q)]=0. |
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