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The production of TV sets in a factory increases uniformly by a fixed number every year . It produced 16000 sets in 6th year and 22600 in 9th year. 1. Find the production in first year.2.Find the production in 8th year.3. Find the production during first 3 years.4. In which year, the production is Rs. 29,200. |
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Answer» ong>Step-by-step explanation: Solution : Let the production during first year be a and let d be the increase in production every year. Then, T6=16000⇒a+5d=16000…(i) andT9=22600⇒a+8d=22600...(ii) On SUBTRACTING (i) from (ii), we get 3d=6600⇒d=2200 Putting d = 2200 in (i), we get a+5×2200=16000⇒a+11000=16000 ⇒a=16000-11000=5000 Thus, a = 5000 and d = 2200. (i) Production during first year, a = 5000 (ii) Production during 8TH year is given by T8=(a+7d)=(5000+7×2200)=(5000+15400)=20400. (iii) Production during first 6 YEARS is given by S6= 6 2
{2a+5d}=3(2×5000+5×2200) =3(10000+11000)=63000 |
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