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The product of three terms in G. P. IS 210 ndIf tho continued product of three numbers in G. P. is 216 and the sum of their |
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Answer» let a/r , a , ar are in GP A/C to question, (a/r ) × a × ar = 216a³ = 216a³ = (6)³ a = 6 again, sum of their products in pair = 156 (a/r ) × a + a × ar + ar × (a/r) = 156 a²/r + a²r + a² = 15636/r + 36r + 36 = 156 36( 1/r + r + 1) = 156 3(r² + r + 1) = 13r 3r² + 3r + 3 - 13r = 03r² -10r + 3 = 03r² - 9r - r + 3 = 0r = 3 and 1/3 so, numbers are 6/3, 6 , 6×3 => 2, 6, 18 numbers are 6×3 , 6 , 6/3 => 18, 6, 2 please like the solution 👍 ✔️ |
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