The product of 4 consecutive positive integers is 840. Find those numb

1.	The product of 4 consecutive positive integers is 840. Find those numbers.
Answer» Step-by-step explanation: Let the consecutive numbers be n, (n+1) , (n + 2 ) (n+ 3). then n(n+1)(n + 2 )(n+ 3) = 840. Add and subtarct 1 to the first NUMBER of the product. if n = 4 we have 4, 5, 6, 7 n = -7 is not POSSIBLE -7 does not BELONGS to the natural number.

The product of 4 consecutive positive integers is 840. Find those numbers.

Answer»

Step-by-step explanation:

Let the consecutive numbers be n, (n+1) , (n + 2 ) (n+ 3). then n(n+1)(n + 2 )(n+ 3) = 840. Add and subtarct 1 to the first NUMBER of the product. if n = 4 we have 4, 5, 6, 7 n = -7 is not POSSIBLE -7 does not BELONGS to the natural number.

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The product of 4 consecutive positive integers is 840. Find those numbers.​

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The product of 4 consecutive positive integers is 840. Find those numbers.