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The product of 3 consecutive integers is 120 then the greatest number is? |
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Answer» GIVEN : the product of 3 consecutive integers is 120 To Find : the GREATEST numbers Solution: the product of 3 consecutive integers is 120 Hence 3 consecutive numbers will be factor of 120 120 = 1 X 120 120 = 2 x 60 120 = 3 x 40 120 = 4 x 30 120 = 5 x 24 120 = 6 x 20 120 = 8 x 15 120 = 10 x 12 So all the factors of 120 are 1 , 2 , 3 , 4 , 5 , 6 , 8 , 10 , 12 , 15 , 20 , 24 , 30 , 40 , 60 , 120 Consecutive factors are: 1 , 2 , 3 , 4 , 5 , 6 1 x 2 x 3 = 6 2 x 3 x 4 = 24 3 x 4 x 5 = 60 4 x 5 x 6 = 120 4 x 5 x 6 = 120 three consecutive integers are 4 , 5 & 6 whose product is 120 and 6 is the greatest number Learn More: show that product of 3 consecutive POSITIVE integer is 6 - Brainly.in If the sum of 3 consecutive integers in ap is 27 and product of first ... |
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