1.

The process is spontaneous at the given temperature, if

Answer»

`Delta H" is " +ve and Delta S " is " -ve`
`Delta H " is " -ve and Delta S " is " +ve`
`Delta H " is " +ve and Delta S " is " +ve`
`Delta H "is " and DeltaS` is EQUAL to zero.

Solution :`Delta G = Delta H - T Delta S` (Gibbs ENERGY EQUATION)
When, `Delta H` is -ve, but `T Delta S` is `+ve rarr Delta G` will be (-ve) [Highly spontaneous].


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