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The probability that a number selected at random from the numbers 1, 2, 3, ..., 15 is a multiple of 4 is(a) 4/15 (b) 2/15 (c) 1/15 (d) 1/5 |
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Answer» The correct option is (d) \(\frac{1}{5}\). Favourable outcomes are 4, 8, 12, i.e., 3 outcomes and total number of outcomes = 15 Required probability = \(\frac{3}{15}\) = \(\frac{1}{5}\). |
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