The probability of an event A occurring is 0.5 and of B is 0.3. If A a

1.	The probability of an event A occurring is 0.5 and of B is 0.3. If A and Bare mutually exclusive events, then find the probability of neither A nor B occurring.
Answer» A and B are mutually exclusive events. ∴P(A∩B)=ϕ=0 Step 2: P(A∪B)=P(A)+P(B)−P(A∩B)⇒0.5+0.3 ⇒0.8 P(A∪B)′=1−P(A∪B) ⇒1−0.8 ⇒0.2 thanks

The probability of an event A occurring is 0.5 and of B is 0.3. If A and Bare mutually exclusive events, then find the probability of neither A nor B occurring.

Answer»

A and B are mutually exclusive events.

∴P(A∩B)=ϕ=0

Step 2:

P(A∪B)=P(A)+P(B)−P(A∩B)⇒0.5+0.3

⇒0.8

P(A∪B)′=1−P(A∪B)

⇒1−0.8

⇒0.2

thanks