Saved Bookmarks
| 1. |
The probability density function (PDF) of a random variable, X is given by,fX(x)=Ke−(x+1)218The value of K will be______.0.133 |
|
Answer» The probability density function (PDF) of a random variable, X is given by, fX(x)=Ke−(x+1)218 The value of K will be______.
|
|