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the price of 3 notebooks and 2 test books is rupees is 135 but a notebook cost rupees 5 more than the test book. Find the cost of both the network and testbook |
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Answer» LET us take the cost of a notebook be'x' let us take the cost of one testbook be 'y' according to the question, 3 notebook and 2 testbook is of 135 RUPEES so, 3x+2y=135.......(1) a notebook cost 5 rupees more than the testbook so, x=y+5 x-y=5.........(2) multiply both sides by 3 in equation 3(x-y)=(3)(5) 3x-3y=15......(3) subtract equation (1) and (3) 3x+2y-(3x-3y)=135-15 3x+2y-3x+3y=120 5y=120 y=120/5 y=24 put the VALUE of y in eq. 2 x-y=5 x-24=5 x=5+24 x=29 |
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