The pressure of water in a pipe when tap is closed is `5.5xx10^(5) Nm^(-2)`. The velocity with which water comes out on opening the tap isA. `10 ms^(-1)`B. `5 ms^(-1)`C. `20 ms^(-1)`D. `15 ms^(-1)`

The pressure of water in a pipe when tap is closed is `5.5xx10^(5) Nm^

1.	The pressure of water in a pipe when tap is closed is `5.5xx10^(5) Nm^(-2)`. The velocity with which water comes out on opening the tap isA. `10 ms^(-1)`B. `5 ms^(-1)`C. `20 ms^(-1)`D. `15 ms^(-1)`
Answer» Correct Answer - A Decrese in pressure energy = increase in kinetic energy `or" "Deltarho=1/2rhov^(2)` `therefore" " v=sqrt((2(DeltaP))/rho)=sqrt((2xx0.5xx10^(5))/(10^(3)))=10 ms^(-1)`

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The pressure of water in a pipe when tap is closed is `5.5xx10^(5) Nm^(-2)`. The velocity with which water comes out on opening the tap isA. `10 ms^(-1)`B. `5 ms^(-1)`C. `20 ms^(-1)`D. `15 ms^(-1)`

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