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The pressure of h2 required to make the potential of h2 electrode 0 in pure Water at 298k |
Answer» The pressure of H2 REQUIRED to make the potential of H2 electrode 0 in pure water at 298K is 10-¹⁴ atmHydrogen ions get two ions and form hydrogen GAS as below reaction. according to Nernst's equation, E- E0 = - 0.0591/n log[P_(H2)]/[[H+]²] as electrode potential is zero in pure water. i.e., Enet = 0 when [H+] = 10^-7 [ we know, in pure water [H+] = [OH-] = 10^-7], n = 2 so, 0 = 0.0591/2 log[P/(10^-7)²] ⇒Log[P/(10-¹⁴) ] = 0 ⇒P /10-¹⁴ = 1 ⇒P = 10-¹⁴ atm ALSO read similar questions: what is the mass of oxygen required to react completely with 15 g of H2 gas to form water what will be the partial pressure of h2 in a flask containing 2 g of h2, 14g of n2 and 16g of o2 |
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