Saved Bookmarks
| 1. |
The pressure of an ideal gas varies according to the law `P = P_(0) - AV^(2)`, where `P_(0)` and `A` are positive constants. Find the highest temperature that can be attained by the gasA. `(2P_(0))/(3R)(P_(0)/(3alpha))^(1//2)`B. `(2P_(0))/(2R)(P_(0)/(3alpha))^(1//2)`C. `(P_(0))/(R)(P_(0)/(3alpha))^(1//2)`D. `(P_(0))/(R)(P_(0)/(alpha))^(1//2)` |
|
Answer» Correct Answer - 1 `P=P_(0)-alphaV^(2)` `("nRT")/("V")=P_(0)-alphaV^(2)` `RT=P_(0)V-alphaV^(3)" "[becausen=1]` `(dT)/(dV)=(P_(0))/(R)-(3alphaV^(2))/(R)=0` `V=sqrt((P_(0))/(3alpha))` `RT=P_(0)sqrt((P_(0))/(3alpha))-alpha(P_(0))/(3alpha)sqrt((P_(0))/(3alpha))` `T_("max")=(sqrtP_(0))/(sqrt3alphaR)(P_(0)-(P_(0))/(3))=(2P_(0))/(3R)sqrt((P_(0))/(3alpha))` |
|