The pressure of a gas at 100 degree Celsius is 2 atm. When the gas is

1.	The pressure of a gas at 100 degree Celsius is 2 atm. When the gas is heated by keeping the volume constant, at what temperature does the pressure raise to 3 atm?
Answer» The temperature of GAS is 286.5°C Explanation: Given data $\mathbf{ Initial \ Pressure(P_{1})=2 \ atm}$ $\mathbf{ Final \ Pressure(P_{2})=3 \ atm}$ $\mathbf{Initial \ Temperature (T_{1})=100^{\circ} \C=100+273 =373 \ K}$ $\mathbf{Final \ Temperature (T_{2})=Unknown}$ Since volume is constant. From formula of Gay-Lussac's LAW $\mathbf{\frac{T_{2}}{T_{1}}=\frac{P_{2}}{P_{1}}}$ On PUTTING RESPECTIVE value in above equation, we GET $\mathbf{\frac{T_{2}}{373}=\frac{3}{2}}$ On solving, we get $\mathbf{T_{2}=559.5 \ K =(559.5-273)^{\circ} \ C=286.5^{\circ} \ C}$