). The pressure exerted by a body of mass 4kg on an area of 2mis (take g=10m/s) 10 N/mb) 15 N/mc) 20 N/md) 30 N/m

). The pressure exerted by a body of mass 4kg on an area of 2mis (take

1.	). The pressure exerted by a body of mass 4kg on an area of 2mis (take g=10m/s) 10 N/mb) 15 N/mc) 20 N/md) 30 N/m
Answer» Static FRICTION is a self-adjusting force.The limiting VALUE of friction up to which the body stays at rest till it starts moving is given by, F s =μmgwhere μ is the coefficient of static friction.Below that limit, the frictional force is equal to the force applied.Here F s =0.8×4×10=32N ; g=10m/s 2 Whereas force applied is 19N less than the limiting value of friction.Hence Frictional force is 19N.

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). The pressure exerted by a body of mass 4kg on an area of 2mis (take g=10m/s) 10 N/mb) 15 N/mc) 20 N/md) 30 N/m​

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). The pressure exerted by a body of mass 4kg on an area of 2mis (take g=10m/s) 10 N/mb) 15 N/mc) 20 N/md) 30 N/m