The pressure exerted by 12g of an ideal gas at t∘C in a vessel of V L volume is 1 atm. When the temperature is increased by 10∘C in the same vessel the pressure increases by 10%. The value of t is. In this question, we are adding 273 to T1 and T2 to convert it to Kelvin scale as it is in Celsius scale. (1)Then why did we convert it again in the end when we got the answer for T? Isn't it already in the Kelvin scale? (2) and why has the -ve sign emerged in the answer for T?

The pressure exerted by 12g of an ideal gas at t∘C in a vessel of V

1.	The pressure exerted by 12g of an ideal gas at t∘C in a vessel of V L volume is 1 atm. When the temperature is increased by 10∘C in the same vessel the pressure increases by 10%. The value of t is. In this question, we are adding 273 to T1 and T2 to convert it to Kelvin scale as it is in Celsius scale. (1)Then why did we convert it again in the end when we got the answer for T? Isn't it already in the Kelvin scale? (2) and why has the -ve sign emerged in the answer for T?
Answer» The pressure exerted by 12g of an ideal gas at t∘C in a vessel of V L volume is 1 atm. When the temperature is increased by 10∘C in the same vessel the pressure increases by 10%. The value of t is. In this question, we are adding 273 to T₁and T₂ to convert it to Kelvin scale as it is in Celsius scale. (1)Then why did we convert it again in the end when we got the answer for T? Isn't it already in the Kelvin scale? (2) and why has the -ve sign emerged in the answer for T?

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